Pin-ended column buckling load is 2.73% lower than Euler's

https://doi.org/10.18535/ijsrm/v7i2.ec04

Authors

  • Abdulqader Said Al-Najmi Department of Civil Engineering, School of Engineering, the University of Jordan. P.O.Box 13298, Amman 11942, Queen Rania Street, Amman-JORDAN.,, Jordan

A verification calculation was aimed at further proving that the least critical load gives the Euler buckling load for a pin-ended column to be : Pcr=(PI)2*EI/L2. Selecting a parabolic function for this purpose, that meets the boundary conditions and is almost exactly similar to the symmetrical function sin(x). It was expected to obtain a critical load that is larger than the load given by the sine function. The parabolic function produced  LOWER CRITICAL LOAD by about 2.73%.